The Pilot post( The Exam)

Hi Everyone,I am going to use this blog to mainly post puzzles and how to orient yourself in solving them.You can also use python or any other programming language to code the rules and solve the puzzles.

Please keep in mind that I will give orientation to help you solve the puzzle and also the name of the book which contains the puzzle.I will give the answer after some days

So Let's get started with the first puzzle below

The Exam:-

Five students-Adele, Betty, Carol, Doris, and Ellen answered five questions on an exam consisting of two multiple-choice (a, b, or c) questions and three true-or-false (t or f) questions.

[1] They answered the questions as follows:

           1 2 3 4 5
Adele   a a  t  t  t
Betty    b b t  f  t
Carol    a b t  t  f
Doris    b c t  t  f
Ellen    c a f  t  t


[2] No two students got the same number of correct
answers.

Who got the most correct answers?

Orientation:-

1) We need to find the upper limit of correct answers

Since no student got the same number of correct answers 

Lets define the upper limit as 5 then the distinct values for 5 students can be 0,1,2,3,4,5

Lets define the upper limit as 4 then the distinct values for 5 students can be 0,1,2,3,4.

Lets define the upper limit as 3 then there is only 0,1,2,3 which only gives for 4 students so the upper limit is 4,5 only.

2)

i)Substitue 5 answers as correct for each of the five students and see if no two students got the same number of correct answers. 

ii) if (i) fails then it means the maximum number of current answer is 4 and minimum is 0, hence find out which students can have 0 correct answers and find its inverse to find all the correct answers for the 5 question and solve the problem.

iii)This puzzle is contained in the book "The Great book of puzzles and teasers by George J Summers".




Comments

Post a Comment

Popular posts from this blog

A Warm Farewell

  A Warm Farewell:- At a train station, the Porter family is saying good-bye to the Robinson f amily. We don't know who is leaving and who is staying. Each of the members of the Porter family says farewell to each of the members of the Robinson family. To say good bye, two men shake hands, and both a man and a woman and two women kiss once on the cheek. An eyewitness to the event counted 21 handshakes and 34 kisses.   . How many men and how many women were saying good-bye ?? Orientation: - 1)First find the total number of members in each family by adding the handshakes and kisses 21+34=55 interactions and then find the factors of 55 ie 5* 11, 55* 1. 55 * 1 is not possible hence there are 5 members in one family and 11 members in another family. 2) Using the same logic find the no of mens in each family with 21 handshakes. 3) Use 1 and 2 to find the number of women in each family 4) Give the total number of men and women based on 2 and 3.
Read more

The Newspaper and the Cryptophone

The Third one is simple one below 3.The Newspaper:- A boy found 2 sheets of a newspaper. One sheet was numbered 1 - 2 - 71 - 72 the other was   numbered  13 - 14 -  ? - ? The other two numbers  in ?  had been torn off.  What were they  ?? Orientation:- i)If you have the habit of reading newspaper this is a simple one ,if not go and buy one to solve this puzzle. The fourth is a bit tough 4.Cryptophone :- Can you decipher the coded quotation below the dial?  Each number  represents one of the letters shown with it on the telephone dial. A number does not necessarily represent the same letter each time. Dial 0:- Dial 1:-ABC Dial 2:-DEF Dial 3:-GHI Dial 4:-JKL Dial 5:-MNO Dial 6:-PQR Dial 7:-STU Dial 8:-VWX Dial 9:-YZ Cipher text below:- 15 56735377 37 1  515 835 771677 1 165778562 679942 8373 1  25757135 625. Orientation:- i) Try to solve the smaller text first and see solving the remanining text makes sense Fo...
Read more

Answers for Puzzles 8 to 11

  Answers:- The Calender:- Every year divisible by 4 without remainder is bissextile (leap year), except that every year divisible by 100 without remainder is not leap year, unless it be also divisible by 400 without remainder, when it is leap year. This is not generally understood. Thus 1800 was not leap year, nor was 1900; but 2000, 2400, 2800, etc., will all be leap years. The first day of the present century, January I, 1901, was Tuesday. The present century will contain 25 leap years, because 2000 is leap year, and therefore 36,525 (365 X 100 + 25) days, or 5217 weeks and 6 days; so that January 1,2001, will be 6 days later than Tuesday-that is Monday. The century beginning January I, 2001, will contain only 24 leap years, because 2100 is not leap year, and January 1,2101, will be 5 days later than Monday, last mentioned, that is Saturday, because there are 5217 weeks and only 5 days.   It will now be convenient to put the...
Read more